Subject: Re: [xsl] XPath for expressing contiguous elements? From: "Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Mon, 1 May 2017 14:21:28 -0000 |
not(*[not(self::A)][following-sibling::A][preceding-sibling::A]) returns true if and only if there is no non-A element that is both preceded and followed by an A element, which I think is equivalent to your expression and rather simpler. Michael Kay Saxonica > On 1 May 2017, at 14:00, Costello, Roger L. costello@xxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > Hi Folks, > > I want an XPath expression that implements this rule: > > All <A> elements shall be contiguous within <Test>. > > In this example all A's are contiguous, so the rule is satisfied: > > <Test> > <B/> > <A/> > <A/> > <A/> > <B/> > </Test> > > In this example there is an intervening B, so the rule is not satisfied: > > <Test> > <B/> > <A/> > <A/> > <B/> > <A/> > <B/> > </Test> > > Below is the XPath that I created. I have two questions about it: > > (1) Is it correct? Do you see anything it would fail to catch? > > (2) Is there a better (simpler, more efficient) XPath expression? > > Here is the XPath (within a Schematron rule): > > <sch:rule context="Test"> > <sch:assert test=" > every $i in A satisfies > (if ($i/preceding-sibling::A) then $i/preceding-sibling::*[1][self::A] else true()) > and > (if ($i/following-sibling::A) then $i/following-sibling::*[1][self::A] else true()) > "> > All A's shall be contiguous within Test. > </sch:assert> > </sch:rule>
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