Subject: Re: [xsl] XPath for expressing contiguous elements? From: "Alan Painter alan.painter@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Mon, 1 May 2017 16:34:03 -0000 |
If it's possible to use some XSLT2.0 to set up a variable before then checking it via XPATH, could use the group-adjacent feature of for-each-group to set up a variable $adjacentAs <xsl:variable name="adjacentAs" as="element(adjacentAs)*> <xsl:for-each-group select="/Test/*" group=adjacent="name(.)"> <xsl:if test="name(.) eq 'A'"> <adjacentAs> <xsl:copy-of select="current-group()" /> </adjacentAs> </xsl:if> </xsl:for-each-group> </xsl:variable> The xpath test would then be: count($adjacentAs) gt 1 best regards On Mon, May 1, 2017 at 5:07 PM, Dimitre Novatchev dnovatchev@xxxxxxxxx < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > Here is one without any negation: > > /*/A[preceding-sibling::A][following-sibling::A] > [preceding-sibling::*[1][self::A]] > [following-sibling::*[1][self::A]] > and true() > > > On Mon, May 1, 2017 at 7:21 AM, Michael Kay mike@xxxxxxxxxxxx > <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > not(*[not(self::A)][following-sibling::A][preceding-sibling::A]) > > > > returns true if and only if there is no non-A element that is both > preceded and followed by an A element, which I think is equivalent to your > expression and rather simpler. > > > > Michael Kay > > Saxonica > > > > > >> On 1 May 2017, at 14:00, Costello, Roger L. costello@xxxxxxxxx < > xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > >> > >> Hi Folks, > >> > >> I want an XPath expression that implements this rule: > >> > >> All <A> elements shall be contiguous within <Test>. > >> > >> In this example all A's are contiguous, so the rule is satisfied: > >> > >> <Test> > >> <B/> > >> <A/> > >> <A/> > >> <A/> > >> <B/> > >> </Test> > >> > >> In this example there is an intervening B, so the rule is not satisfied: > >> > >> <Test> > >> <B/> > >> <A/> > >> <A/> > >> <B/> > >> <A/> > >> <B/> > >> </Test> > >> > >> Below is the XPath that I created. I have two questions about it: > >> > >> (1) Is it correct? Do you see anything it would fail to catch? > >> > >> (2) Is there a better (simpler, more efficient) XPath expression? > >> > >> Here is the XPath (within a Schematron rule): > >> > >> <sch:rule context="Test"> > >> <sch:assert test=" > >> every $i in A satisfies > >> (if ($i/preceding-sibling::A) then $i/preceding-sibling::*[1][self::A] > else true()) > >> and > >> (if ($i/following-sibling::A) then $i/following-sibling::*[1][self::A] > else true()) > >> "> > >> All A's shall be contiguous within Test. > >> </sch:assert> > >> </sch:rule> > >> > > > > > > -- > Cheers, > Dimitre Novatchev > --------------------------------------- > Truly great madness cannot be achieved without significant intelligence. > --------------------------------------- > To invent, you need a good imagination and a pile of junk > ------------------------------------- > Never fight an inanimate object > ------------------------------------- > To avoid situations in which you might make mistakes may be the > biggest mistake of all > ------------------------------------ > Quality means doing it right when no one is looking. > ------------------------------------- > You've achieved success in your field when you don't know whether what > you're doing is work or play > ------------------------------------- > To achieve the impossible dream, try going to sleep. > ------------------------------------- > Facts do not cease to exist because they are ignored. > ------------------------------------- > Typing monkeys will write all Shakespeare's works in 200yrs.Will they > write all patents, too? :) > ------------------------------------- > Sanity is madness put to good use. > ------------------------------------- > I finally figured out the only reason to be alive is to enjoy it.
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