Subject: Re: [xsl] difficulty using xsl:analyze-string From: "Liam R. E. Quin liam@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 18 Jul 2018 06:05:39 -0000 |
On Wed, 2018-07-18 at 05:34 +0000, Mukul Gandhi gandhi.mukul@xxxxxxxxx wrote: > [...] > <xsl:analyze-string select="'hello world\nexperimenting > with > XSLT\nhow are you'" regex="\n"> Remember that \ isn't special in XML or XPath strings, so your string contains literal backslashes followed by lower case n. In a regular expression \ is special however, so to match a literal backslash-n you want \\n insteaf of \n. Liam -- Liam Quin, W3C, http://www.fromoldbooks.org/ Available for stuff.
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] difficulty using xsl:analyze-, Mukul Gandhi gandhi. | Thread | Re: [xsl] difficulty using xsl:anal, Mukul Gandhi gandhi. |
[xsl] difficulty using xsl:analyze-, Mukul Gandhi gandhi. | Date | Re: [xsl] difficulty using xsl:anal, Mukul Gandhi gandhi. |
Month |