<-prev [Thread] next-> <-prev [Date] next->
Month Index | List Home

Re: [xsl] difficulty using xsl:analyze-string

Subject: Re: [xsl] difficulty using xsl:analyze-string
From: "Mukul Gandhi gandhi.mukul@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Wed, 18 Jul 2018 06:39:55 -0000
On Wed, Jul 18, 2018 at 11:35 AM, Liam R. E. Quin liam@xxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> Remember that \ isn't special in XML or XPath strings, so your string
> contains literal backslashes followed by lower case n. In a regular
> expression \ is special however, so to match a literal backslash-n you
> want \\n insteaf of \n.


Thanks, Liam. Your suggestion solves my problem.

I've some other questions as below, related to xsl:analyze-string,

1) The 1st example here, https://www.w3.org/TR/xslt20/#regex-examples

specifies regex as \n. That probably got me wrong.

2) The output I receive, has <br> instead of <br/>. I specified <br/> in my
stylesheet. The output I'm getting might be probably because, I
have <xsl:output method="html"/> in the stylesheet.
When I change output spec to following, <xsl:output method="xhtml"/> I
get <br></br> in the output.

When I specify, xsl:output method="xhtml", the following is the complete
output I get,

<?xml version="1.0" encoding="UTF-8"?><html>
   <head>
      <title>test</title>
   </head>
   <body>hello world
      <br></br>experimenting with XSLT
      <br></br>how are you
   </body>
</html>

Shouldn't an XHTML document begin with something like,

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>

<html xmlns="http://www.w3.org/1999/xhtml";>





-- 
Regards,
Mukul Gandhi
Current Thread
<- PreviousIndexNext ->
Re: [xsl] difficulty using xsl:anal, Liam R. E. Quin liam Thread Re: [xsl] difficulty using xsl:anal, David Carlisle d.p.c
Re: [xsl] difficulty using xsl:anal, Liam R. E. Quin liam Date Re: [xsl] difficulty using xsl:anal, David Carlisle d.p.c
Month