Subject: Re: [xsl] XSLT repetition constructs From: "Mukul Gandhi gandhi.mukul@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Fri, 8 Mar 2019 09:42:30 -0000 |
On Fri, Mar 8, 2019 at 2:10 PM Michael Kay mike@xxxxxxxxxxxx < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > Because if $a is an empty sequence (which is the situation on the first > call), then $a[last()] is an empty sequence, and ($x + ()) returns an empty > sequence, not $x. > Thanks, for the explanation. I came up with following as well, which works (though may be inefficient) <xsl:variable name="inpValues" select="(1,2,3,4)" as="xs:integer*"/> fold-left($inpValues, (), function($a, $b) {$a, sum(for $idx in 1 to count($a) return $inpValues[$idx]) + $b}) -- Regards, Mukul Gandhi
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