Re: [xsl] is XPath 3.1 xml-to-json() function useful

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 08.03.2019 23:07, Willem Van Lishout willemvanlishout@xxxxxxxxx wrote:
> I've been experimenting with the xml-to-json function, but for some 
> reason my output is escaped. Why is that?
>
> Stylesheet:
>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>  B B B  xmlns:xs="http://www.w3.org/2001/XMLSchema"; 
> xmlns:f="http://www.w3.org/2005/xpath-functions"; version="3.0">
>  B B B  <xsl:output encoding="UTF-8" method="json"/>
>  B B B  <xsl:template match="/">
>  B B B B B B B  <xsl:variable name="transformed">
>  B B B B B B B B B B B  <xsl:apply-templates select="programs"/>
>  B B B B B B B  </xsl:variable>
>  B B B B B B B  <xsl:value-of select="xml-to-json($transformed, map{'indent': 
> true()})"/>

The function returns a string you can output as such with the xsl:output 
method="text", you have used "json" instead which then applies JSON 
escaping rules on the string you have.