Re: [xsl] Keeping result-document() from writing to a file more than once?

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 19.04.2019 17:02, Eliot Kimber ekimber@xxxxxxxxxxxx wrote:

> If you construct map entries for each use and then combine them into a
single map using the "use-first" or "use-any" "duplicates" option then you can
blindly process all the references and let the map-merge process produce a
single list of elements, e.g.;
> <xsl:variable name="use-entries" as="map(*)*">
>    <xsl:call-template name="find-all-conrefs"/>
> </xsl:variable>
>
> The find-all-conrefs template generates maps, one for each id/element pair,
which you can create with xsl:map or using the literal map constructor:
"map{$key : $value}".
> Now make a single map:
>
> <xsl:variable name="use-map" as="map(*)"
>    select="map:merge($use-entries, map{ 'duplicates' : 'use-any'}"
> />
>
> And then process the entries to produce the result docs:
>
> <xsl:for-each select="map:keys($use-map)">
>    <xsl:variable name="key" select="." as="xs:string"/>
>    <xsl:call-template name="make-result-doc">
>      <xsl:with-param name="key" as="xs:string" select="$key"/>
>      <xsl:with-param name="key" as="element() " select="map:get($use-map,
$key)" as="element() "/>

Isn't that second parameter supposed to be named
       <xsl:with-param name="value" as="element() "
select="map:get($use-map, $key)" as="element() "/>
?

>    </xsl:call-template>
> </xsl:for-each>