Re: [xsl] Keeping result-document() from writing to a file more than once?

["Eliot Kimber ekimber@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Yes--thanks for catching that--cut and paste error.

Cheers,

E.

--
Eliot Kimber
http://contrext.com


o;?On 4/19/19, 10:10 AM, "Martin Honnen martin.honnen@xxxxxx"
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

    On 19.04.2019 17:02, Eliot Kimber ekimber@xxxxxxxxxxxx wrote:

    > If you construct map entries for each use and then combine them into a
single map using the "use-first" or "use-any" "duplicates" option then you can
blindly process all the references and let the map-merge process produce a
single list of elements, e.g.;
    >
    > <xsl:variable name="use-entries" as="map(*)*">
    >    <xsl:call-template name="find-all-conrefs"/>
    > </xsl:variable>
    >
    > The find-all-conrefs template generates maps, one for each id/element
pair, which you can create with xsl:map or using the literal map constructor:
"map{$key : $value}".
    >
    > Now make a single map:
    >
    > <xsl:variable name="use-map" as="map(*)"
    >    select="map:merge($use-entries, map{ 'duplicates' : 'use-any'}"
    > />
    >
    > And then process the entries to produce the result docs:
    >
    > <xsl:for-each select="map:keys($use-map)">
    >    <xsl:variable name="key" select="." as="xs:string"/>
    >    <xsl:call-template name="make-result-doc">
    >      <xsl:with-param name="key" as="xs:string" select="$key"/>
    >      <xsl:with-param name="key" as="element() "
select="map:get($use-map, $key)" as="element() "/>

    Isn't that second parameter supposed to be named
            <xsl:with-param name="value" as="element() "
    select="map:get($use-map, $key)" as="element() "/>
    ?

    >    </xsl:call-template>
    > </xsl:for-each>