Subject: Re: [xsl] XPath expression that yields the same result as xsl:for-each-group? From: "David Carlisle d.p.carlisle@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 30 May 2019 12:49:48 -0000 |
You could make it an xpath, but you don't _need_ to do that to store it in a variable , simply use xsl:variable with content rather than a select attribute.
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