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Subject: Re: [xsl] Is this a grouping task? From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 22 Oct 2019 18:41:44 -0000 |
I am using XSLT 2 and think this may require a for-each-group solution. Any advice would be appreciated. Thank you very much.
As an alternative, if you can move to XSLT 3, then I think it is also easy with "xsl:iterate":
<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="#all" version="3.0">
<xsl:mode name="rev-change" on-no-match="shallow-copy" streamable="yes"/>
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/> <xsl:template match="topic">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:iterate select="*">
<xsl:param name="rev-change" as="xs:boolean"
select="false()"/>
<xsl:apply-templates select="." mode="rev-change">
<xsl:with-param name="rev-change"
select="$rev-change" tunnel="yes"/>
</xsl:apply-templates>
<xsl:next-iteration>
<xsl:with-param name="rev-change"
select="if (self::revst) then true()
else if (self::revend) then false()
else $rev-change"/>
</xsl:next-iteration>
</xsl:iterate>
</xsl:copy>
</xsl:template> <xsl:template mode="rev-change" match="topic/*">
<xsl:param name="rev-change" tunnel="yes"/>
<xsl:copy>
<xsl:if test="$rev-change">
<xsl:attribute name="rev">changed</xsl:attribute>
</xsl:if>
<xsl:apply-templates select="@*" mode="#current"/>
<xsl:apply-templates mode="#current"/>
</xsl:copy>
</xsl:template>| Current Thread |
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