Subject: Re: [xsl] compare two node sets From: "David Birnbaum djbpitt@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sun, 19 Jan 2020 20:40:20 -0000 |
Dear Wolfhart, You may find http://www.xqueryfunctions.com/xq/functx_sequence-deep-equal.html useful. Best, David On Sun, Jan 19, 2020 at 3:36 PM Wolfhart Totschnig wolfhart.totschnig@xxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > Hello, > > I have an XSL/XPath problem to which I cannot find the solution. I have > an xml file with data about films, in the following form (simplified): > > <film> > <title>The big Lebowski</title> > <director> > <first>Joel</first> > <last>Coen</last> > </director> > <director> > <first>Ethan</first> > <last>Coen</last> > </director> > <author> > <first>Ethan</first> > <last>Coen</last> > </author> > <author> > <first>Joel</first> > <last>Coen</last> > </author> > </film> > > I would like to test whether the director(s) of the film are the same as > its writer(s) (here called "authors"). That is, I want to test whether > for each <director> element there is an <author> element with the same > child elements, and vice versa (i.e., for each <author> element a > corresponding <director> element). So, in the above case, the test > should return <true>. Note that the order of the <director>/<author> > elements should not matter. By contrast, in the following example the > test should return <false>: > > <film> > <title>M</title> > <director> > <first>Fritz</first> > <last>Lang</last> > </director> > <author> > <first>Thea von</first> > <last>Harbou</last> > </author> > <author> > <first>Fritz</first> > <last>Lang</last> > </author> > </film> > > How can this be done? > > To explain the purpose of this: When the test comes out true, the output > will be "Written and directed by [names]", whereas otherwise it will be > "Written by [names]. Directed by [names]". > > Thanks in advance for your help! > > Wolfhart
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