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Re: [xsl] compare two node sets

Subject: Re: [xsl] compare two node sets
From: "Mukul Gandhi gandhi.mukul@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Tue, 21 Jan 2020 13:21:43 -0000
On Mon, Jan 20, 2020 at 2:19 AM Michael Kay mike@xxxxxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:


> The simplest (XPath 2.0) solution that comes to mind is
>
> count(//director) eq count(//author) and
> every $d in //director satisfies
>   some $a in //author satisfies
>     deep-equal($d/*, $a/*)
>

+1

(with the improvisation suggested by Martin)



-- 
Regards,
Mukul Gandhi

http://member.acm.org/~mukulgandhi
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