Re: [xsl] Grouping

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Am 21.10.2020 um 17:25 schrieb Christoph Naber pentium120mhz@xxxxxxxxx:

> the question of Charlie brought me to thinking about a problem and
> solution that I came up with a few years ago.
> A few words upfront:
> - This is a _very_ stripped down example which doesn't reflect the
> complete structure. I hope that I was able to retain all relevant
> structural attributes that shape the solution.
> - I included <parentA> and <parentB> in the example to account for the
> fact that there are at least 20 different parents where the relevant
> <points> can occur as childs. It's also possible that a parent holds
> relevant <points>, completely different nodes and also another parent.
> - I don't want to include <xsl:for-each-group > in every possible parent
> for the sake of maintainability. Because of the loads of different child
> nodes it seems to me atm that it's not sensible to write specialized
> select-statements in apply-templates. Just select="@* | node()" and let
> the child-nodes "somehow" take care of themselves.

Can you explain the criteria to "group"/wrap "point" elements without
having to infer that from the XSLT you posted?

Using
  <xsl:template match="*[point]">
    <xsl:copy>
      <xsl:for-each-group select="*" group-adjacent="...">
in my view seems preferable but I haven't quite understood which point
elements have to be wrapped.