Re: [xsl] Find/replace algorithm

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 24.03.2021 21:38, Martin Honnen martin.honnen@xxxxxx wrote:
> On 24.03.2021 21:28, rick@xxxxxxxxxxxxxx wrote:
> > Hello All,
> >
> > I have a fairly large XML file similar to this:
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> >
> > <products>
> >
> >      <product>ACME Wid Assbly</product>
> >
> >      <product>Ford Eng Rebuild Kit</product>
> >
> > </products>
> >
> > I want to do an identity transform except that I want to do some find
> > and replace on some of the words. For example
> >
> > Wid = Widget
> >
> > Assbly = Assembly
> >
> > Eng = Engine
> >
> > I am thinking of creating a lookup XML file to drive the find/replace
> > actions:
> >
> > <?xml version="1.0" encoding="UTF-8"?>
> >
> > <lookup>
> >
> >      <entry find="\bWid\b" replace="Widget"/>
> >
> >      <entry find="\bAssbly\b" replace="Assembly"/>
> >
> >      <entry find="\bEng\b" replace="Engine"/>
> >
> > </lookup>
> >
> > I am having trouble figuring out a good XSLT 2 or 3 algorithm for
> > actually doing the replacements. Any suggestions or pointers would be
> > appreciated. Thank you very much.
>
> Perhaps using fold-left or xsl:iterate for the replace, together with
> the ;j or ;n flag to enable support for \b:

The fold-left might be more compact but requires Saxon 10 HE or PE or EE
for earlier versions:

  <xsl:template match="product/text()">
    <xsl:value-of select="fold-left($lookup/lookup/entry, .,
function($w, $e) { replace($w, $e/@find, $e/@replace, ';j') })"/>
  </xsl:template>