Re: [xsl] Find/replace algorithm

["Michael Kay mike@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

My instinct would be

(a) build a map containing the replacements

(b) for each text node, tokenize the content, then scan the tokens looking
each one up in the map.

The big advantage of this approach is that the cost is constant regardless how
many substitutions there are, whereas most other approaches have a cost that
increases linearly with the number of substitutions.

Michael Kay
Saxonica

> On 24 Mar 2021, at 20:28, rick@xxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>
> Hello All,
>
> I have a fairly large XML file similar to this:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <products>
>     <product>ACME Wid Assbly</product>
>     <product>Ford Eng Rebuild Kit</product>
> </products>
>
> I want to do an identity transform except that I want to do some find and
replace on some of the words. For example
>
> Wid = Widget
> Assbly = Assembly
> Eng = Engine
>
> I am thinking of creating a lookup XML file to drive the find/replace
actions:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <lookup>
>     <entry find="\bWid\b" replace="Widget"/>
>     <entry find="\bAssbly\b" replace="Assembly"/>
>     <entry find="\bEng\b" replace="Engine"/>
> </lookup>
>
> I am having trouble figuring out a good XSLT 2 or 3 algorithm for actually
doing the replacements. Any suggestions or pointers would be appreciated.
Thank you very much.
>
> Rick
>
> Rick Quatro
> Carmen Publishing Inc.
> 585-729-6746
> rick@xxxxxxxxxxxxxxx <mailto:rick@xxxxxxxxxxxxxxx>
> http://www.frameexpert.com/store <http://www.frameexpert.com/store>
>
>
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