Re: [xsl] Sibling recursion?

["Norm Tovey-Walsh ndw@xxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

> I would be grateful for any insights.

This seems to work, YMMV.

<xsl:template match="p">
  <p>
    <xsl:for-each-group select="node()"
                        group-adjacent="self::q or self::text()[normalize-space(.)='']">
      <xsl:choose>
        <xsl:when test="current-grouping-key()">
          <q>
            <xsl:for-each select="current-group()">
              <xsl:if test="position() gt 1">
                <xsl:text> </xsl:text>
              </xsl:if>
              <xsl:sequence select="node()"/>
            </xsl:for-each>
          </q>
        </xsl:when>
        <xsl:otherwise>
          <xsl:sequence select="current-group()"/>
        </xsl:otherwise>
      </xsl:choose>
    </xsl:for-each-group>
  </p>
</xsl:template>

                                        Be seeing you,
                                          norm

--
Norman Tovey-Walsh <ndw@xxxxxxxxxx>
https://nwalsh.com/

> We are at the very beginning of time for the human race. It is not
> unreasonable that we grapple with problems. But there are tens of
> thousands of years in the future. Our responsibility is to do what we
> can, learn what we can, improve the solutions, and pass them
> on.--Richard Feynman

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