Subject: Re: [xsl] Sibling recursion? From: "David Birnbaum djbpitt@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 3 Mar 2022 18:04:55 -0000 |
Dear xsl-list, Thanks to everyone for the quick responses, and especially to Norm for sharing the template that I should have written in the first place. Best, David On Thu, Mar 3, 2022 at 11:23 AM Norm Tovey-Walsh ndw@xxxxxxxxxx < xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > > I would be grateful for any insights. > > This seems to work, YMMV. > > <xsl:template match="p"> > <p> > <xsl:for-each-group select="node()" > group-adjacent="self::q or > self::text()[normalize-space(.)='']"> > <xsl:choose> > <xsl:when test="current-grouping-key()"> > <q> > <xsl:for-each select="current-group()"> > <xsl:if test="position() gt 1"> > <xsl:text> </xsl:text> > </xsl:if> > <xsl:sequence select="node()"/> > </xsl:for-each> > </q> > </xsl:when> > <xsl:otherwise> > <xsl:sequence select="current-group()"/> > </xsl:otherwise> > </xsl:choose> > </xsl:for-each-group> > </p> > </xsl:template> > > Be seeing you, > norm > > -- > Norman Tovey-Walsh <ndw@xxxxxxxxxx> > https://nwalsh.com/ > > > We are at the very beginning of time for the human race. It is not > > unreasonable that we grapple with problems. But there are tens of > > thousands of years in the future. Our responsibility is to do what we > > can, learn what we can, improve the solutions, and pass them > > on.--Richard Feynman
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