Re: [xsl] How to sort based on the number of child elements?

["Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

>  I cannot use xsl:sort for this, right?

Why not?

See my reply using <xsl:sort> to solve the problem.

On Mon, May 9, 2022 at 10:31 AM Roger L Costello costello@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

> Hi Folks,
>
> I have an XML Schema that contains a xs:choice. I want to sort the
> branches of the choice, in longest-to-shortest order.
>
> Here is a xs:choice with two branches:
>
> <xs:choice>
>     <xs:element name="MilitaryDayTime">
>         <xs:complexType>
>             <xs:sequence>
>                 <xs:element name="Day" type="xs:string"/>
>                 <xs:element name="HourTime" type="xs:string"/>
>                 <xs:element name="MinuteTime" type="xs:string"/>
>                 <xs:element name="TimeZone" type="xs:string"/>
>             </xs:sequence>
>         </xs:complexType>
>     </xs:element>
>     <xs:element name="DateTimeGroup">
>         <xs:complexType>
>             <xs:sequence>
>                 <xs:element name="Day" type="xs:string"/>
>                 <xs:element name="HourTime" type="xs:string"/>
>                 <xs:element name="MinuteTime" type="xs:string"/>
>                 <xs:element name="TimeZone" type="xs:string"/>
>                 <xs:element name="MonthName" type="xs:string"/>
>                 <xs:element name="Year" type="xs:string"/>
>             </xs:sequence>
>         </xs:complexType>
>     </xs:element>
> </xs:choice>
>
> The first branch is an element with 4 child elements. The second branch is
> an element with 6 child elements. So sorting the branches
> longest-to-shortest will result in reversing the order of the branches.
>
> I cannot use xsl:sort for this, right?
>
> Is there an easy solution to this task?
>
> /Roger
> 
>
>

-- 
Cheers,
Dimitre Novatchev
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