[xsl] efficiently extracting a capture group from analyze-string()

["Chris Papademetrious christopher.papademetrious@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hi everyone!

Given some filename string like

  <xsl:variable name="file" select="'path/my-sometype.xml'"/>

I'd like to extract the "my-(\w+)" part of the filename using
analyze-string(). So far I have

  <xsl:variable name="my-file-type" select="data(analyze-string($file,
'my-(\w+)')//fn:group[1])"/>

which works by extracting the <group> descendant from the
<analyze-string-result> tree, then converting it to text. Is there a more
concise way to do this?

I had to define

  xmlns:fn=http://www.w3.org/2005/xpath-functions

in my stylesheet for fn:group to match, and I'm not sure if there's a better
way to do that too.

Thanks!


  *   Chris

-----
Chris Papademetrious
Tech Writer, Implementation Group
(610) 628-9718 home office
(570) 460-6078 cell