[xsl] Re: efficiently extracting a capture group from analyze-string()

["Chris Papademetrious christopher.papademetrious@xxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hi Gerrit, Graydon,

Thanks for having a look!

The tricky part is, I need an empty sequence if the input string does not
comply with pattern. replace() returns the original string for a non-match. I
could address that with a prefilter:

  replace($file[matches(., '/my-(\w+)\.xml$')], '^.+/my-(\w+)\.xml$', '$1')

but I don't like duplicating patterns because they can accidentally become
desynchronized. (If anyone suggests an ENTITY as a solution here, please see
me after class.)

Graydon, I need your solution for obtaining the file basename elsewhere in my
stylesheet -- thank you!! -- but I run into the prefilter double-pattern issue
whether I replace()the full path or just the basename.

And although this example processes a filename, I'd like to find best
generalized way to obtain a capture group (or nothing) for any match scenario.
In perl, I can assign a variable to the result of a regex match:

  my $file = 'path/my-sometype.xml';
  my ($type) = ($file =~ m{my-(\w+)});

and I was hoping for something similar in XQuery.

Thank you everyone! It's nice to be able to group-think through this.

- Chris


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