Re: [xsl] Process the following group

["Eliot Kimber eliot.kimber@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

So the first two div2 elements should be grouped with the first div1?

If you do group-starting-with div1 then the first two div2s will be in the
first group and that group will not start with a div1, so you can have logic
to ignore that first group and then in a group that starts with <div1>, you
can pull any <div2> elements that do not have a <div1> preceding sibling,
which will get the <div2>s that would have formed the first group. No
subsequent group will have <div2>s that do not have a <div1> preceding
sibling.

But this is also a case where it might be easier to pre-process your content
before grouping, for example, to move things so that theres always a <div1>
before any <div2>s or what ever it might be.

I generally find these kinds of challenges are most effectively solved by
breaking them into several steps, each one of which is relatively easy to
implement.

Cheers,

E.
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Eliot Kimber
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From: rick@xxxxxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Thursday, July 7, 2022 at 4:49 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: Re: [xsl] Process the following group
[External Email]

The reason I was looking at this is sometimes the order of the groups changes
in the output. So, if I have this:

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <div2/>
    <div2/>
    <div1/>
    <div1/>
    <div2/>
    <div2/>
    <div1/>
</root>

I sometimes need this:

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <div1>
        <div2/>
        <div2/>
    </div1>
    <div1>
        <div2/>
        <div2/>
    </div1>
    <div1/>
</root>

In other words, in the final output, any non-div1 elements have to be included
in the first div1 to make the output document valid.

Rick
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