Re: [xsl] Process the following group

["rick@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hi Eliot, thank you for walking me through the logic. It makes sense so I
will try to code it that way. But I think the advice from you and others to
do a multiple pass may be a more robust approach. Thanks to all that
responded. -Rick

 

From: Eliot Kimber eliot.kimber@xxxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> 
Sent: Thursday, July 7, 2022 6:11 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Process the following group

 

So the first two div2 elements should be grouped with the first div1?

 

If you do group-starting-with div1 then the first two div2s will be in the
first group and that group will not start with a div1, so you can have logic
to ignore that first group and then in a group that starts with <div1>, you
can pull any <div2> elements that do not have a <div1> preceding sibling,
which will get the <div2>s that would have formed the first group. No
subsequent group will have <div2>s that do not have a <div1> preceding
sibling.

 

But this is also a case where it might be easier to pre-process your content
before grouping, for example, to move things so that there's always a <div1>
before any <div2>s or what ever it might be.

I generally find these kinds of challenges are most effectively solved by
breaking them into several steps, each one of which is relatively easy to
implement.

 

Cheers,

 

E.