Re: [xsl] XPath expression that returns the first 10 leaf element within the airport element?

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 22.07.2022 13:51, Roger L Costello costello@xxxxxxxxx wrote:
> My XML document has an <airport> element:
>
> <airport>
>      <a>blah</a>
>     <b>
>        <c>blah</c>
>     </b>
>     ...
> </airport>
>
> I want the first 10 leaf elements within the <airport> element (<a>, <c>,
...).
> I thought this XPath would do the job:
>
> <xsl:for-each select="airport//*[not(child::*)][position() le 10]">
>
> But that XPath does not return the first 10 leaf elements. It returns over
nine thousand elements!
> What is that XPath expression saying? Clearly it is saying something
different than I thought it was saying.
> I think I found the correct XPath expression:
>
> <xsl:for-each select="(airport//*[not(child::*)])[position() le 10]">
>
> Do you agree that that XPath expression will select the first 10 leaf
elements within the <aircraft> element?
>
An easy to make mistake with positional predicates and // in your
initial attempt but you corrected it well.

I sometimes tend to avoid the trap doing

B  airport/descendant::*[not(*)][position() le 10]