Re: [xsl] XPath expression that returns the first 10 leaf element within the airport element?

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On 22.07.2022 14:15, Martin Honnen martin.honnen@xxxxxx wrote:
> On 22.07.2022 13:51, Roger L Costello costello@xxxxxxxxx wrote:
> > My XML document has an <airport> element:
> >
> > <airport>
> > B B B B  <a>blah</a>
> > B B B  <b>
> > B B B B B B  <c>blah</c>
> > B B B  </b>
> > B B B  ...
> > </airport>
> >
> > I want the first 10 leaf elements within the <airport> element (<a>,
> > <c>, ...).
> >
> > I thought this XPath would do the job:
> >
> > <xsl:for-each select="airport//*[not(child::*)][position() le 10]">
> >
> > But that XPath does not return the first 10 leaf elements. It returns
> > over nine thousand elements!
> >
> > What is that XPath expression saying? Clearly it is saying something
> > different than I thought it was saying.
> >
> > I think I found the correct XPath expression:
> >
> > <xsl:for-each select="(airport//*[not(child::*)])[position() le 10]">
> >
> > Do you agree that that XPath expression will select the first 10 leaf
> > elements within the <aircraft> element?
> An easy to make mistake with positional predicates and // in your
> initial attempt but you corrected it well.
>
> I sometimes tend to avoid the trap doing
>
> B  airport/descendant::*[not(*)][position() le 10]

I think XPath 3 also allows you

B B  airport/innermost(.//*)[position() le 10]