Re: [xsl] XPath expression which converts the output of path() into an abbreviated path?

["Norm Tovey-Walsh ndw@xxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

> I am using the path() function and it is generating paths like this:
>
> /Q{}AeroPublication[1]/Q{}airports[1]/Q{}airport[1]/Q{}icaoCode[1]
>
> Now I want to convert that full path into an abbreviated path, consisting of
just the last 3 names:
>
> airports/airport/icaoCode
>
> I can write a bunch of XSLT code that does this conversion. But is
> there an XPath expression which does it?

Off the top of my head, you can replace bQ{}b and b[1]b with the
empty
string, tokenize on b/b, get the last three members, and string-join
them back together with b/b.

Youbll have to exercise a little more care if the elements might be in a
namespace or if you might get some other index (b[2]b for example).

This works, but I canbt immediately think of a way to avoid the $parts
variable. But someone cleverer than me will probably post a purely
functional answer thatbs eluding me.

  <xsl:variable name="path"
                select="'/Q{}AeroPublication[1]/Q{}airports[1]/Q{}airport[1]/
Q{}icaoCode[1]'"/>

  <xsl:variable name="parts"
                select="replace($path, 'Q\{\}', '')
                        => replace('\[\d+\]', '')
                        => tokenize('/')"/>
  <xsl:sequence select="string-join($parts[count($parts) - position() lt 3],
'/')"/>

                                        Be seeing you,
                                          norm

--
Norman Tovey-Walsh <ndw@xxxxxxxxxx>
https://nwalsh.com/

> He that will not apply new remedies must expect new evils; for time is
> the great innovator.--Sir Francis Bacon

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