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Subject: Re: [xsl] XPath expression which converts the output of path() into an abbreviated path? From: "Norm Tovey-Walsh ndw@xxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 17 Aug 2022 12:54:25 -0000 |
> This works, but I canbt immediately think of a way to avoid the $parts
> variable. But someone cleverer than me will probably post a purely
> functional answer thatbs eluding me.
*blush* Just tokenize first rather than last.
Be seeing you,
norm
--
Norman Tovey-Walsh <ndw@xxxxxxxxxx>
https://nwalsh.com/
> We navigate our whole lives using words. Change and improve the words
> and I believe we can change and improve life.
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