Re: [xsl] XPath expression which converts the output of path() into an abbreviated path?

["Eliot Kimber eliot.kimber@xxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

I would probably do:


(//info[1]/ancestor-or-self::* => tail())  ! local-name(.) =>
string-join('/')

To get all the but the root element in the path. The => appears to put the
ancestor nodes into document order.

Cheers,

E.

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From: Piez, Wendell A. (Fed) wendell.piez@xxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Date: Thursday, August 18, 2022 at 3:36 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: Re: [xsl] XPath expression which converts the output of path() into
an abbreviated path?
[External Email]


Hi,

Joel is right: that is a much better approach.

ancestor-or-self::*[position() = (1 to 3)]/local-name(.) => string-join('/')

Unless I am not mistaken this will collect three levels up - while the /
provides for the return sequence to be read top-down (document order) not
bottom up. (Correct?)

Cheers, Wendell


-----Original Message-----
From: Joel Kalvesmaki director@xxxxxxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Thursday, August 18, 2022 3:04 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Cc: Roger L Costello costello@xxxxxxxxx
<xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>
Subject: Re: [xsl] XPath expression which converts the output of path() into
an abbreviated path?

Here's another approach, if the XPath expression has icaoCode as the context.
Forget about path(). Just string-join the local names of the ancestors and
self, e.g.,

string-join(for $i in (ancestor-or-self::* except /*) return local-name($i),
'/')

jk

On 2022-08-17 08:22, Roger L Costello costello@xxxxxxxxx wrote:
> Hi Folks,
>
> I am using the path() function and it is generating paths like this:
>
> /Q{}AeroPublication[1]/Q{}airports[1]/Q{}airport[1]/Q{}icaoCode[1]
>
> Now I want to convert that full path into an abbreviated path,
> consisting of just the last 3 names:
>
> airports/airport/icaoCode
>
> I can write a bunch of XSLT code that does this conversion. But is
> there an XPath expression which does it?
>
> /Roger
>

--
Joel Kalvesmaki
Director, Text Alignment Network
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