Aw: [xsl] Copy XPATH

["Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

XSLT/XPath 3 have a "path()" function. 

I am trying to copy XPATH along with attributes value in an OUTPUT xml
file.
XML:<bb>
<as id="ENCA" major.version="6" minor.version="0">
<tl>The Title</tl>
<b/>
<ts id="ENCA_GC">
<tl>TS Title text</tl>
<st jr="IB" id="EA_T1">
<tl>ST Title Text</tl>
<st.body>
<pr>
<sp>
<sp.txt align="centre" cont="n">
<emphasis type="bold" shading="nil">INTRODUCTION</emphasis>
</sp.txt>
</sp>
</pr>
</st.body>
</st>
</ts>
</as>
</bb>
Output Required
<as title="The Title" xpath="bb/as[1]" id=" <ts title="TS Title text"
xpath="bb/as[1]/ts[1]" id="ENCA_GC">
<st jr="IB" title="ST Title Text" xpath="/bb/as[1]/ts[1]/st[1]"
id="EA_T1"/>
<st.body xpath="bb/as[1]/ts[1]/st[1]/st.body[1]">
<pr xpath="bb/as[1]/ts[1]/st[1]/st.body[1]/pr[1]">
<sp xpath="bb/as[1]/ts[1]/st[1]/st.body[1]/pr[1]/sp[1]"/>
<sp.txt count="n"
xpath="bb/as[1]/ts[1]/st[1]/st.body[1]/pr[1]/sp[1]/sp.txt[1]">
</sp.txt>
</pr>
</st.body>
</ts>
</as>
XSL:
<xsl:template match="as">
<xsl:element name="as">
<xsl:attribute name="title">
<xsl:value-of select="title/node()"/>
</xsl:attribute>
<xsl:attribute name="xpath">
<xsl:value-of select ="local-name()"/>
</xsl:attribute>
</xsl:element>
</xsl:template>

<xsl:template match="ts">
<xsl:element name="ts">
<xsl:attribute name="title">
<xsl:value-of select="title/node()"/>
</xsl:attribute>
<xsl:attribute name="xpath">
<xsl:value-of select="fn:generateXPath(guidecard)"/>
</xsl:attribute>
</xsl:element>
</xsl:template>

<xsl:function name="fn:generateXPath" as="xs:string">
<xsl:param name="pNode" as="node()"/>
<xsl:for-each select="$pNode/ancestor::*">
<xsl:value-of select="name()" />
</xsl:for-each>
</xsl:function>

<xsl:template match="st.body" >
<st.body>
<xsl:value-of select="fn:generateXPath(st.body)"/>
</st.body>
</xsl:template>
Please suggest.
Thanks
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