Re: [xsl] Copy XPATH

["Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

As Martin Honnen noted, in XPath or XSLT ver 3+ one can use the standard
path() function - https://www.w3.org/TR/xpath-functions-31/#func-path

For a solution with XSLT 1.0 (or 2.0) see this Stack Overflow answer:
https://stackoverflow.com/a/4747858/36305

Thanks,
Dimitre

On Mon, Nov 11, 2024 at 7:28b/AM Byomokesh Sahoo sahoo.byomokesh@xxxxxxxxx <
xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote:

>
> Hi,
>
> I am trying to copy XPATH along with attributes value in an OUTPUT xml
> file.
>
> XML:
> <bb>
> <as id="ENCA" major.version="6" minor.version="0">
>     <tl>The Title</tl>
>     <b/>
>     <ts id="ENCA_GC">
>         <tl>TS Title text</tl>
>         <st jr="IB" id="EA_T1">
>             <tl>ST Title Text</tl>
>             <st.body>
>                 <pr>
>                     <sp>
>                         <sp.txt align="centre" cont="n">
>                             <emphasis type="bold"
> shading="nil">INTRODUCTION</emphasis>
>                         </sp.txt>
>                     </sp>
>                 </pr>
>             </st.body>
>         </st>
>     </ts>
> </as>
> </bb>
>
> Output Required
>
> <as title="The Title" xpath="bb/as[1]" id="ACLL.CA">
>         <ts title="TS Title text" xpath="bb/as[1]/ts[1]" id="ENCA_GC">
>             <st jr="IB" title="ST Title Text"
> xpath="/bb/as[1]/ts[1]/st[1]" id="EA_T1"/>
>             <st.body xpath="bb/as[1]/ts[1]/st[1]/st.body[1]">
>                 <pr xpath="bb/as[1]/ts[1]/st[1]/st.body[1]/pr[1]">
>                     <sp
> xpath="bb/as[1]/ts[1]/st[1]/st.body[1]/pr[1]/sp[1]"/>
>                     <sp.txt count="n"
> xpath="bb/as[1]/ts[1]/st[1]/st.body[1]/pr[1]/sp[1]/sp.txt[1]">
>                 </sp.txt>
>             </pr>
>         </st.body>
>     </ts>
> </as>
>
> XSL:
>
> <xsl:template match="as">
>         <xsl:element name="as">
>             <xsl:attribute name="title">
>                 <xsl:value-of select="title/node()"/>
>             </xsl:attribute>
>         <xsl:attribute name="xpath">
>             <xsl:value-of select ="local-name()"/>
>         </xsl:attribute>
>         </xsl:element>
>     </xsl:template>
>
>     <xsl:template match="ts">
>         <xsl:element name="ts">
>             <xsl:attribute name="title">
>                 <xsl:value-of select="title/node()"/>
>             </xsl:attribute>
>             <xsl:attribute name="xpath">
>                 <xsl:value-of select="fn:generateXPath(guidecard)"/>
>             </xsl:attribute>
>         </xsl:element>
>     </xsl:template>
>
>     <xsl:function name="fn:generateXPath" as="xs:string">
>         <xsl:param name="pNode" as="node()"/>
>         <xsl:for-each select="$pNode/ancestor::*">
>             <xsl:value-of select="name()" />
>         </xsl:for-each>
>     </xsl:function>
>
>     <xsl:template match="st.body" >
>         <st.body>
>         <xsl:value-of select="fn:generateXPath(st.body)"/>
>         </st.body>
>     </xsl:template>
>
> Please suggest.
>
> Thanks
>
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