Re: [xsl] Is there a way in XSLT/XPath to find the portion of a string that matches a pattern?

["Liam R. E. Quin liam@xxxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On Tue, 2025-03-11 at 22:12 +0000, Roger L Costello costello@xxxxxxxxx
wrote:
> Liam gave this wicked cool way to return the portion of a string that
> matches a regex pattern:
>
> replace($input, '^.*(\d+).*$', '$1')
>
> However, I did some testing, and it's not returning the desired
> results:

Changing the initial .* to .*? (non-greedy) will fix this, as the .
will no longer match a digit and eat away at the integer.

This is because the .* is greedy by default, and eats as much of the
start of the string as possible, leaving only one digit for the \d (or
[0-9] if you prefer).


My bad, i should have tested before posting, sorry!

In this case, ^[^\d]*(\d+).*$' would be a variant that is more obvious,
but that doesnt work for a general pattern.

If you use the input 'The person put 203 cookies into 3 jars'
you can see the .* approach will return 3 and the .*? will return 203.

liam

--
Liam Quin,B https://www.delightfulcomputing.com/
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