[xsl] Rearrange order of processed nodes

["Michael Mueller-Hillebrand michael.mueller-hillebrand@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

Hello, dear colleagues,

We have a task to process certain child elements before all other child nodes
are processed. The obvious, simple solution would be something like:

<xsl:apply-templates select="elem1, node() except elem1"/>

But in our case, we have six named elements that should be processed before
all other child nodes. And the repetition of the node list seems not very
nice:

<xsl:apply-templates select="(elem1|elem2|elem3|elem4|elem5|elem6), node()
except (elem1|elem2|elem3|elem4|elem5|elem6)"/>

Yes, I could collect the special elements in a variable and use this.

<xsl:variable name="specialElems"
select="(elem1|elem2|elem3|elem4|elem5|elem6)" as="element()+"/>
<xsl:apply-templates select="$specialElems, node() except $specialElems"/>

Do you have other suggestions which I cannot see because my brain is not
relaxed enough?

Thanks a lot,
Michael


Michael MC<ller-Hillebrand
Senior Consultant
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