RE: transforming unique nodes thru XSLT

[Kay Michael <Michael.Kay@xxxxxxx>]

You can do something like:
 
for-each select="//b"
  variable name="item" select="@item"/
  variable name="remainder" select="following::item[@item=$item]"/
  if test="not($remainder)"
     ... do the output ...
  /if
/for-each
  

-----Original Message-----
From: Anand K [mailto:anandk@xxxxxxxxx]
Sent: 24 September 1999 03:38
To: xsl-list@xxxxxxxxxxxxxxxx
Subject: transforming unique nodes thru XSLT


Hello everyone, 

I have an XSL Transformation question. I hope I can raise XSLT issues here.
I am new to XSL and want to write a template 
to transform only unique nodes from a well formed XML document to HTML. 


Below is a small snippet of this well formed document which I want to
transform 
<xyz> 
    ... 
    ... 
    <a name="school"> 
        <a name="grade5"> 
            <b item="pencil"/> 
            <b item="paper"/> 
        </a> 
        <a name="grade10"> 
            <b item="pen"/> 
            <b item="paper"/> 
            <b item="backpack"/> 
        </a> 
    </a> 
    <a name="office"> 
        <b item="cuibicle"/> 
        <b item="paper"/> 
        <a name="engg"> 
            <b item="pc"/> 
            <b item="backpack"/> 
        </a> 
    </a> 
    .... 
    ... 
</xyz> 


Now, from this XML document I want to create a HTML document which would be
a list of all the 'b' element's attributes 
(i.e. item). As you see there are a few items which are repeated in the XML
document. If I want only the unique elements 
depending on b's attribute item then how should go about writing the XSLT
template. Is this possible? Maybe I have to parse 
the entire document more than once to see if a particular node is unique,
but how to do this? Any help!!! 


PS: I am using  XT (Ver 19990822) by James Clark for the transformation. 


Thank you, 
Anand 
  
  


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