outputting the "position()" of parent

[Justin Friedl <justin.friedl@xxxxxxxxxxxxx>]

How do I output the posistion of the parent.  I can output the position of
the current node like this:
<xsl:value-of select="position()"/>

So I thought I could do this:
<xsl:value-of select="../position()"/>
but it doesn't work.... any suggestions?

thanks in advance
Justin


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list