[xsl] copying attributes

["Russ Holmes" <rholmes@xxxxxxxxx>]

When converting the result of three SQL queries to xml I generate something
like;

<breakfasts>

    <life_to_date>
        <z breakfast="bacon"     servings="2000"/>
        <z breakfast="eggs"       servings="2000"/>
        <z breakfast="cereal"     servings="7000"/>
    </life_to_date>

    <y2000>
        <z breakfast="bacon"   servings="130">
        <z breakfast="eggs"     servings="100">
    </y2000>

    <january>
        <z breakfast="eggs"     servings="1">
    </january>

</breakfasts>


..you can assume that any 'breakfast' types in the y2000 and january nodes
will show in the life_to_date node..

I would like to load this xml into a Data Source Object using the following
format;

<z breakfast="bacon"    january_servings=""      y2000_servings="130"
life_to_date_servings="2000"/>
<z breakfast="eggs"     january_servings="1"     y2000_servings="100"
life_to_date_servings="2000"/>
<z breakfast="cereal"   january_servings=""       y2000_servings=""
life_to_date_servings="7000"/>

Can I transform into this format?  If so how?

In trying to create the 'january_servings' node I've tried;

<xsl:template match="/breakfasts/life_to_date/z">
  <z>
    <xsl:for-each select="@breakfast" >
    <xsl:attribute name="breakfast"><xsl:value-of
select="."/></xsl:attribute>
    <xsl:attribute name="january_servings"><xsl:value-of
select="/breakfasts/january[@breakfast=.]/@servings"/>
    </xsl:attribute>
    </xsl:for-each>
</z>
</xsl:template>

But with no success...could anyone help me out here? I'm trying to say for
each life_to_date/z node, iterate through the 'breakfast' attributes and
create new attributes with values that match the value of the corresponding
'january' node..where the 'breakfast' attibutes match..

Thanks heaps,

Russ


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