Subject: RE: [xsl] Can sets have order? From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Fri, 2 Feb 2001 01:58:39 -0800 (PST) |
>There is no query which yields visibly different results. ????? There are ***many*** Xpath expressions, which will produce different results when you swap the two nodes: 1. generate-id($node) 2. count($node/preceding::node()) 3. count($nodeset[position() < 4 and count(preceding::*) = $num1]) The above is constructed assuming that node1 and node2 are respectively $nodeset[3] and $nodeset[5] and that $num1 is equal to count(node1/preceding::*) The expression count($nodeset[position() < 4 and count(preceding::*) = $num1]) will evaluate to 1 given the original nodeset. It will evaluate to 0 on the nodeset in which the deep-equal nodes node1 and node2 were swapped. Dimitre. __________________________________________________ Get personalized email addresses from Yahoo! Mail - only $35 a year! http://personal.mail.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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