Re: [xsl] catching the last node still satisfying a condition

[Guillaume Rousse <rousse@xxxxxxxxxxxxxx>]

Ainsi parlait Dimitar Peikov :
[..]
> > Considering the following situation
> > <foo>
> >   <foo id="foo1">
> >     <bar/>
> >   </foo>
> >   <foo id="foo2">
> >   <bar/>
> >   </foo>
> >   <foo id="foo3>
> >   </foo>
> > </foo>
> > i would like to catch foo2 with limit = 2 or 3, and foo1 with limit = 1
>
> foos/foo[position() &lt; limit]/bar
Inside a for-each to catch only the last, that's OK: 
<xsl:for-each select="foos/foo[bar and position() &lt; limit]">
  <xsl:if test="position()=last()">
    <xsl:apply-template select="."/>
  </xsl:if>
</xsl:for-each>
Thanks
-- 
Guillaume Rousse <rousse@xxxxxxxxxxxxxx>
GPG key http://lis.snv.jussieu.fr/~rousse/gpgkey.html

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