AW: [xsl] Getting at original document from inside document()

[Ursprung Manfred <Manfred.Ursprung@xxxxxxxxxx>]

One way would be to store root of original document in a variable.
Like:
<xsl:variable name="original" select="/" />

This should work.

- Manfred

> -----Ursprüngliche Nachricht-----
> Von:	Phil Endecott [SMTP:spam-from-xsl-list@xxxxxxxxxxxx]
> Gesendet am:	Dienstag, 23. Oktober 2001 15:25
> An:	XSL-List@xxxxxxxxxxxxxxxxxxxxxx
> Betreff:	[xsl] Getting at original document from inside document()
> 
> Dear XSL experts,
> 
> Once I am in a document selected by a document() function, is there
> any way to refer to nodes in the original source document?
> 
> Here's a (contrived) example: I have this as my main source document:
> 
> <book title="foo">
>   <chapter src="chap1.xml"/>
> </book>
> 
> Then I have a stylesheet that does something like:
> 
> <xsl:template match="chapter">
>   <xsl:apply-templates select="document(@src)/*"/>
> </xsl:template>
> 
> and then somewhere deep in the processing of the chapter's contents I
> want to use the book's title.  At first I naively tried /book/@title -
> but that doesn't work, because / is the root of chap1.xml, not of the
> source document.  I could use document('....')/book/@title, if I knew
> what the name of the original source file was: but I don't.
> 
> I was hoping that something like document('')/book/@title would get
> the answer, but it looks like this gets the stylesheet, not the
> original input document.
> 
> Of course there are various hacks to get or fix the filename that
> could have the desired effect, but I was hoping that someone would
> know of a "clean" way to do this.
> 
> Any ideas anyone?
> 
> Maybe there is a case for adding something to the next XSL to do this?
> 
> Thanks,
> 
> --Phil.
> 
> 
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