Subject: [xsl] Q on ISO TimeDate convertion From: "Walter Torres" <walter@xxxxxxxxx> Date: Wed, 7 Nov 2001 19:48:01 -0600 |
I have an XSLT Template that converts the ISO TimeDate format to an American Standard display. 2001-10-18T12:27:46 10/18/2001 12:27:46 My problem is that I really don't know how to convert the Time part to an AM/PM format, not just the 24 hour clock it is now. Below is the code I am using to convert the date. Can someone help with the Time conversion. Also, is there a way to pass the ISO Date/Time and return the conversion, just a function? The Template I have does the conversion and the display all within the Template. Walter <!-- timestamp NODE Template --> <xsl:template match="timestamp"> <!-- Pull the pieces apart --> <xsl:variable name="datetime" select="."/> <xsl:variable name="year" select="substring( $datetime, 0 , 5 )"/> <xsl:variable name="month" select="substring( $datetime, 6 , 2 )"/> <xsl:variable name="day" select="substring( $datetime, 9 , 2 )"/> <td valign="top" class='data'> <!-- put the date together in American order --> <xsl:value-of select="concat($month, '/', $day, '/', $year )"/> <!-- Seperate the date and Time --> - <!-- Display the Time --> <xsl:value-of select="substring( $datetime, 12 , 5 )"/> </td> </xsl:template> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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