Subject: RE: [xsl] Reformatting tables From: Jarno.Elovirta@xxxxxxxxx Date: Thu, 29 Nov 2001 14:49:07 +0200 |
> How can I write some xsl to reformat this into proper rows? Eg: <xsl:template match="tr[count(td[1]/p) > 1]"> <xsl:for-each select="td[1]/p"> <tr> <td><p><xsl:value-of select="."/></p></td> <xsl:variable name="n" select="position()"/> <td><p><xsl:value-of select="../../td[2]/p[position()=$n]"/></p></td> </tr> </xsl:for-each> </xsl:template> <xsl:template match="tr"> <xsl:copy-of select="." /> </xsl:template> J XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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