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Subject: [xsl] Reformatting tables From: "Neil Abraham" <mylists@xxxxxxxxxxxxxxxxx> Date: Thu, 29 Nov 2001 12:27:40 -0000  | 
Hi all,
I have a large number of html tables in the following format:
<table>
  <tr>
    <td>
      <p>Animal</p>
    </td>
    <td>
      <p>Colour</p>
    </td>
  </tr>
  <tr>
    <td>
      <p>Elephant</p>
      <p>Pig</p>
      <p>Sheep</p>
      <p>Canary</p>
    </td>
    <td>
      <p>Grey</p>
      <p>Pink</p>
      <p>White</p>
      <p>Yellow</p>
    </td>
  </tr>
</table>
Where someone has used FrontPage or something and has ended up creating one
row of multiple paragraphs instead of a row for each item.
How can I write some xsl to reformat this into proper rows?  Eg:
<tr>
  <td>
   <p>Elephant</p>
  </td>
  <td>
   <p>Grey</p>
  </td>
</tr>
So far I have made:
<xsl:template match="tr">
 <xsl:for-each select="td[1]/p">
  <tr>
   <td><p><xsl:value-of select="."/></p></td>
   <xsl:variable name="n" select="position()"/>
   <td><p><xsl:value-of select="//td[2]/p[position()=$n]"/></p></td>
  </tr>
 </xsl:for-each>
</xsl:template>
But this always leaves them out of sync.
What am I doing wrong?
Thanks in advance,
Neil.
PS. Excuse the animal colours example, the real data is confidential
internal stuff :-)
 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
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