Re: [xsl] for-each order

[Jeni Tennison <jeni@xxxxxxxxxxxxxxxx>]

Hi Charly,

> Is there a way to do <xsl:for-each ..... and looping backwards.

Sure. Sort (numerically) on position() in descending order:

  <xsl:for-each select="histo/bar">
    <xsl:sort select="position()" order="descending"
              data-type="number" />
    <xsl:value-of select="@value" />
    <xsl:if test="position() != last()">,</xsl:if>
  </xsl:for-each>

Note that the call to position() in the select attribute of the
xsl:sort looks at the order of the selected nodes in the document,
whereas the call to position() within the xsl:for-each looks at the
sorted order of the nodes as they're being processed.
  
I hope that helps,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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