Re: [xsl] for-each order

[Trevor Nash <tcn@xxxxxxxxxxxxx>]

>Is there a way to do <xsl:for-each ..... and looping backwards.
>

Use xsl:sort, as in:

><xsl:variable name="position">
>   <xsl:for-each select="$path">
       <xsl:sort select="position()" data-type="number"
order="descending" />
>      <xsl:value-of select="@value"/>,
>   </xsl:for-each>
></xsl:variable>

(Ref: Mike Kay's XSLT programmers reference, page 297)

Anticipating the obvious question if you want 1,2,3 instead of 1,2,3,
  <xsl:if test="position()!=last()">,</xsl:if>

Regards,
Trevor Nash
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