RE: [xsl] how to rearrange nodes based on a dependency graph

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RE: [xsl] how to rearrange nodes based on a dependency graph?

Subject: RE: [xsl] how to rearrange nodes based on a dependency graph?
From: "Chris Bayes" <chris@xxxxxxxxxxx>
Date: Thu, 20 Dec 2001 21:26:05 -0000

What about
<xsl:for-each select='*[not(@requires)]'>
	<xsl:call-template name='copy-stuff'/>
</xsl:for-each>

Ciao Chris

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Current Thread
[xsl] how to rearrange nodes based on a dependency graph? Gunther Schadow - Thu, 20 Dec 2001 14:20:21 -0500 Chris Bayes - Thu, 20 Dec 2001 21:26:05 -0000 <= Chris Bayes - Thu, 20 Dec 2001 21:41:15 -0000 Gunther Schadow - Thu, 20 Dec 2001 17:00:47 -0500 Chris Bayes - Thu, 20 Dec 2001 22:29:52 -0000 Gunther Schadow - Thu, 20 Dec 2001 17:52:35 -0500

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