RE: [xsl] how to rearrange nodes based on a dependency graph?

["Chris Bayes" <chris@xxxxxxxxxxx>]

Or even
<xsl:key name='fragkey' match='frag' use='@id' />
<xsl:template match="frag[@requires]">
	<xsl:for-each select="@requires">
		<xsl:for-each select="key('fragkey',.)[not(@requires)]">
			<xsl:copy-of select="." />
		</xsl:for-each>
	</xsl:for-each>
	<xsl:copy-of select="." />
</xsl:template>
<xsl:template match="frag" />

Hey it's christmas. I don't use ids and idrefs. If this <xsl:for-each
select="@requires"> returns all of the idrefs then this might work. But
if it doesn't then mine is a stella and a bacardi and coke hick!

Ciao Chris

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