Subject: RE: [xsl] how to select the same attribute form more elements? From: "Andrew Welch" <awelch@xxxxxxxxxxxxxxx> Date: Thu, 14 Feb 2002 16:55:49 -0000 |
>> I dont think there is a single expression to return all the attributes. >> >> Also, /myxml/node/text() should return only 't1' (as it is the only text in >> the first node) and /myxml/node/@val should return the first attribute > >No. >/myxml/node/text() as well as /myxml/node/@val select node-sets. Sure - it depends in where you use the xpath. Since he mentioned that /myxml/node/text() returns all the text, and he was after a 'single expression', I was assuming he was doing <xsl:value-of select="...."/> In my defence also offered: <xsl:template match="/"> <xsl:apply-templates select="myxml/node"/> </xsl:template> <xsl:template match="node"> <xsl:value-of select="@val"/> </xsl:template> ...which is more new-user friendly than using a for-each as you suggested ;) cheers andrew XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] how to select the same at, Oliver Becker | Thread | [xsl] position() returning incorrec, jon wa |
Re: [xsl] match on attribute anywhe, Wendell Piez | Date | Re: [xsl] xsl:number, Wendell Piez |
Month |