Subject: Re: [xsl] sort | uniq via keys From: "Thomas B. Passin" <tpassin@xxxxxxxxxxxx> Date: Thu, 14 Feb 2002 12:32:02 -0500 |
My post from February 11,2002, with the title "Re: [xsl] Many sets of eyes " shows how to get a unique list of elements sorted by names (unique meaning that each element name occurs once). That should be close enough to get you started. Cheers, Tom P [Saverio Perugini]> > I am interested in a sorted and uniqed list of all element names in > an XML file (except for the root), similar to `sort | uniq' in UNIX. > > e.g., in the following data, > > <db> > <a>...</a> > <z>...</z> > <g>...</g> > <j> > <f>...</f> > <z>...</z> > <a><o>...</o></a> > </j> > <b>...</b> > <b>...</b> > </db> > > I'd like the following list > > a > b > f > g > j > o > z > > I am trying to achieve this with keys (unless someone can direct me to > a simpler method). The following is an initial attempt. > > <xsl:key name="features" match="*" use="name()"/> > > <xsl:template match="/db"> > > <xsl:for-each select="following::*[count (. | key('features', name())[1]) = 1]"> > <xsl:sort select="name()" /> > <xsl:value-of select="name()" /><xsl:text> > </xsl:text> > </xsl:for-each> > > </xsl:template> > > <xsl:template match="text()"/> > > This is not working out however. It returns an empty file. Does this > appear to be correct? > XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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