Re: [xsl] sort | uniq via keys

[Saverio Perugini <sperugin@xxxxxxxxxxxxxxxx>]

On Thu, 14 Feb 2002, Wendell Piez wrote:

> Using the following:: axis on your for-each, you are selecting nodes from
> those following your context node, the '/db' you have matched on.
>
> But your db is your document element, and has no following nodes.
>
> Just select your descendants (select="descendant::*[...]) and it should work.

Thank you Wendell.

I am curious then as to the difference b/t the descendant, following,
and following-sibling axes.

In addition, consider the following problem.  Instead of sorting and uniqing the
element names of `all' nodes in the input tree, I'd like to extract
the names of elements residing at the same `level' in the input tree, assuming a
balanced input tree.

e.g.,

in the following data

<db>
   <a>
      <d>
         <j>...</j>
         <k>...</k>
      </d>
      <e>
         <l>...</l>
         <m>...</m>
      </e>
   </a>
   <b>
      <f>
         <n>...</n>
         <o>...</o>
      </f>
      <g>
         <p>...</p>
         <q>...</q>
      </g>
   </b>
   <c>
      <h>
         <r>...</r>
         <s>...</s>
      </h>
      <i>
         <t>...</t>
         <u>...</u>
      </i>
   </c>
</db>

I would like the following output,

first level
-----------
a b c

second level
------------
d e f g h i

third level
-----------
j k l m n o p q r s t u

The following is my initial solution.

<xsl:template match="/db" priority="0.7">
   <xsl:apply-templates select="*[1]"/>
</xsl:template>

<xsl:template match="*">

   <xsl:for-each select="following-sibling::*">
      <xsl:sort select="name()"/>
      <xsl:value-of value="name()" />
  </xsl:for-each>

  <xsl:apply-templates select="*[1]"/>

</xsl:template>

<xsl:template match="text()"/>

This runs down the left-most path of the tree and collects siblings.
The problem is that is works at the sibling level, while I am
interested in an `entire' level in the tree.

Thank You and Best Regards,

Saverio Perugini


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