Re: [xsl] sort | uniq via keys

[Joerg Pietschmann <joerg.pietschmann@xxxxxx>]

Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> wrote:
> [Saverio wrote:]
> >I'd like to extract
> >the names of elements residing at the same `level' in the input tree,
> 
> There are (at least) two ways to approach this. One would be to declare
> different keys for different levels, such as
>   <xsl:key name="features1" match="/*/*" use="name()"/>

The following key generalizes this:
    <xsl:key name="features-level" match="*"
         use="concat(count(ancestor::*)),'#',name())"/>
Us this for example as follows
   <xsl:for-each select="/descendant::*[count(.|key('features-level',concat(count(ancestor::*)),'#',name())))=1]">
    
BTW: May i remind all posters (in particular those who recently
started to post) to trim unnecessary quotes? Those are really
messing up the digest.

Regards
J.Pietschmann

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