Subject: RE: [xsl] xsl:copy From: Jarno.Elovirta@xxxxxxxxx Date: Tue, 19 Feb 2002 08:23:39 +0200 |
Hi > I need to generate a copy of an xml file using xsl ...I tried using > xsl:copy..but this gives me only the value and not the node > names ....Is > there a workaround to accomplish this. With xsl:copy, this would to it <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> but it's easier with xsl:copy-of, i.e. <xsl:template match="/"> <xsl:copy-of select="."> </xsl:template> Santtu XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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