RE: [xsl] xsl:copy

Subject: RE: [xsl] xsl:copy
From: Jarno.Elovirta@xxxxxxxxx
Date: Tue, 19 Feb 2002 08:23:39 +0200
Hi

>   I need to generate a copy of an xml file using xsl ...I tried using
> xsl:copy..but this gives me only the value and not the node 
> names ....Is
> there a workaround to accomplish this.

With xsl:copy, this would to it

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

but it's easier with xsl:copy-of, i.e.

<xsl:template match="/">
  <xsl:copy-of select=".">
</xsl:template>

Santtu

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Current Thread