[xsl] xsl:copy

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[xsl] xsl:copy

Subject: [xsl] xsl:copy
From: "Garrick Besterwitch" <garrickb@xxxxxxxxxxx>
Date: Tue, 19 Feb 2002 11:39:29 +0530

Hi,
  I need to generate a copy of an xml file using xsl ...I tried using
xsl:copy..but this gives me only the value and not the node names ....Is
there a workaround to accomplish this.

Thanks and cheers
Garry


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Current Thread
RE: evaluate() function in XPath 2.0 (Was: Re: [xsl] Lookup (?)) Curtis Burisch - Mon, 18 Feb 2002 17:49:15 +0000 Oleg Tkachenko - Mon, 18 Feb 2002 20:23:52 +0200 Jeni Tennison - Mon, 18 Feb 2002 18:55:32 +0000 Garrick Besterwitch - Tue, 19 Feb 2002 11:39:29 +0530 <= Michael Kay - Tue, 19 Feb 2002 09:30:28 -0000

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